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x^2-8.2x-14.55=0
a = 1; b = -8.2; c = -14.55;
Δ = b2-4ac
Δ = -8.22-4·1·(-14.55)
Δ = 125.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8.2)-\sqrt{125.44}}{2*1}=\frac{8.2-\sqrt{125.44}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8.2)+\sqrt{125.44}}{2*1}=\frac{8.2+\sqrt{125.44}}{2} $
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